(x+1)(x^3+x^2-8x-12)=0

Simple and best practice solution for (x+1)(x^3+x^2-8x-12)=0 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (x+1)(x^3+x^2-8x-12)=0 equation: 


Simplifying
(x + 1)(x3 + x2 + -8x + -12) = 0

Reorder the terms:
(1 + x)(x3 + x2 + -8x + -12) = 0

Reorder the terms:
(1 + x)(-12 + -8x + x2 + x3) = 0

Multiply (1 + x) * (-12 + -8x + x2 + x3)
(1(-12 + -8x + x2 + x3) + x(-12 + -8x + x2 + x3)) = 0
((-12 * 1 + -8x * 1 + x2 * 1 + x3 * 1) + x(-12 + -8x + x2 + x3)) = 0
((-12 + -8x + 1x2 + 1x3) + x(-12 + -8x + x2 + x3)) = 0
(-12 + -8x + 1x2 + 1x3 + (-12 * x + -8x * x + x2 * x + x3 * x)) = 0
(-12 + -8x + 1x2 + 1x3 + (-12x + -8x2 + x3 + x4)) = 0

Reorder the terms:
(-12 + -8x + -12x + 1x2 + -8x2 + 1x3 + x3 + x4) = 0

Combine like terms: -8x + -12x = -20x
(-12 + -20x + 1x2 + -8x2 + 1x3 + x3 + x4) = 0

Combine like terms: 1x2 + -8x2 = -7x2
(-12 + -20x + -7x2 + 1x3 + x3 + x4) = 0

Combine like terms: 1x3 + x3 = 2x3
(-12 + -20x + -7x2 + 2x3 + x4) = 0

Solving
-12 + -20x + -7x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

See similar equations:

| 3x+7-18x=14 | | (7w^2-2w+16)-4(7w^2+15)=0 | | 1/2(2x+8)=2x | | 9y+8y+38= | | -3x-1/4=0 | | -2(x-7)+5x= | | 9r-34+-4r=-39 | | -130=5x-4(4x+5) | | 30n^4+15n^2+1=0 | | 1/2(4x+8)=2x | | X^3-7x^2+25x+8=0 | | 2t-18+-5t=24 | | 34=-5-6t+3r | | 148-s-(4s-5)=2(s+3) | | x^4-38+72=0 | | 6y+x=2x+12y | | 0.7x-4.1y=0 | | 0.5t+8=3 | | 15.19+(-1.85)+0.01= | | n^2-10n-88=-5 | | 3(y+4)=8(y-1) | | 6(x+2)=216(x+1) | | X^3-11x^2+9x-99=0 | | 8x+12=11x-3 | | 2a-4b=12 | | 13-6x=-8x+11 | | 4q-7+-11q=14 | | 4x^3+27x^2-24x-120=0 | | 2t+10-6= | | .8x^2+2.6x=-3.2 | | 10.5+p=8.32 | | 4x^2+27x^2-24x-120=0 |

Equations solver categories